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NEW QUESTION: 1
Which license mode does a Local Survivable Processor (LSP) enter when it becomes active?
A. license normal mode
B. license error mode
C. an LSP does not require a license
D. no license mode
Answer: B

NEW QUESTION: 2
SIMULATION
You work as Network Engineer for RADO network Ltd company. You colleague has setup POC simulating customer network to study about the behavior of BGP protocol when routes are exchanged between two different autonomous systems.
Review the topology. You need to identify and fix IBGP and EBGP issues on R1 router.
Topology Details:
AS64520
* R1, R2 and R3 are three routers on AS 64520 and OSPF is IGP routing protocol configured between them.
* IBGP configured between R1, R2, and R3 routers using peer group.
* Loopback0 address is used for IBGP peering, Loopback0 address configured on R1, R2 and R3 are advertised into
BGP domain on AS64525.
AS64525
* RA and RB are two routers on AS64525 and EIGRP is IGP routing protocol configured between them.
* Loopback0 address is used for IBGP peering, Loopback0 address configured on RA and RB advertised into BGP domain on AS64525.
* R1 and RRA from EBGP neighbor relationship using physical interface address.
*R2 and RB from EBGP neighbor relationship using physical interface address.
SIMULATION requirements:
*Identify and fix EBGP neighbor relationship between R1 and R1 routers.
*Identify and fix IBGP neighbor relationship issue between R1 and R2, R1 and R3.
*You are allowed to remove any misconfiguration or incorrect configuration to only fix the issue and other initial configuration that not impacting the issues should not be changed.
* The Final BGP table, after fixing two issues on R1 router should display as shown below


Answer:
Explanation:
Check the complete solution below:
Explanation:
for EBGP and IBGP lab you have to make correction to the configuration in a router R1.
You have only access to Router R1.
R1 and RA should be neighbors through EBGP.
in R1 you will find this command:
(config-router)#Neighbor 209.165.277.2 remote-as 64525
The ip address here is wrong , delete this command using :
(config-router)#No Neighbor 209.165.277.2 remote-as 64525
And replace it with new command with right ip of RA E0/1 interface by typing this command:
(config-router)#Neighbor 209.165.201.2 remote-as 64525
R1 and R2 and R3 are neighbors through IBGP, and R1 use the peer-group IBGP to form neighborship between R1 and
R2, and between R1 and R3, but actually there issue with the IBGP peer-group commands in R1 You will find in R1 these following commands:
(config-router)#neighbor IBGP peer-group
(config-router)#neighbor IBGP remote-as 64550
(config-router)#neighbor IBGP next-hop-self
(config-router)#neighbor IBGP update-source loopback 0
You must correct the Remote-AS for the Peer-Group IBGP to 64520 to form the neighborship correctly.
Watch Out! If you delete the config with "no neighbor IBGP remote-as 64550" you also will delete the following lines:
(config-router)#neighbor IBGP peer-group
(config-router)#neighbor IBGP next-hop-self
(config-router)#neighbor IBGP update-source loopback 0
So don't delete the line regarding the "remote-as".
Just replace it with:
(config-router)#neighbor IBGP remote-as 64520
In the Scenario regarding the Lab, they tell you how the routing-table should look if you have done everything right!
So if you routing-table on R1 looks like the one they posted in the scenario you have done everything right and can go on to the next topic.
You have to use the command "#show ip bgp " to show bgp routing table , don't use "#show ip route" command
Case Study: 1
Ticket 1: Switch Port Trunk
Topology Overview (Actual Troubleshooting lab design is for below network design)
Client Should have IP 10.2.1.3
*
EIGRP 100 is running between switch DSW1 & DSW2
*
OSPF (Process ID 1) is running between R1, R2, R3, R4
*
Network of OSPF is redistributed in EIGRP
*
BGP 65001 is configured on R1 with Webserver cloud AS 65002
*
HSRP is running between DSW1 & DSW2 Switches
*
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002 in the
ISP's network. Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and outside
(209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running on DSW1 and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number 6.
DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a 'proof-of-concept' on several implementations. This involved changing the configuration on one or more of the devices. You will be presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and solution.
Each ticket has 3 sub questions that need to be answered & topology remains same.
Question-1 Fault is found on which device,
Question-2 Fault condition is related to,
Question-3 What exact problem is seen & what needs to be done for solution


Client is unable to ping IP 209.65.200.241
Solution
Steps need to follow as below:-
When we check on client 1 & Client 2 desktop we are not receiving DHCP address from R4
*
Ipconfig ----- Client will be getting 169.X.X.X
On ASW1 port Fa1/0/ 1 & Fa1/0/2 access port VLAN 10 was assigned which is using IP address
*
10.2.1.0/24
Sh run ------- & check for running config of int fa1/0/1 & fa1/0/2
==================================================== interface FastEthernet1/0/1 switchport mode access switchport access vlan 10 interface FastEthernet1/0/2 switchport mode access switchport access vlan 10
= ===================================================
We need to check on ASW 1 trunk port the trunk Po13 & Po23 were receiving VLAN 20 & 200 but not
*
VLAN 10 so that switch could not get DHCP IP address and was failing to reach IP address of Internet

Change required: On ASW1 below change is required for switch-to-switch connectivity..
* int range portchannel13,portchannel23 switchport trunk allowed vlan none switchport trunk allowed vlan 10,200

NEW QUESTION: 3
CORRECT TEXT





Answer:
Explanation:
Here are the solution as below:
Explanation:
First we have to figure out why R3 and R4 can not communicate with each other. Use the show running-config command on router R3.

Notice that R3 is configured as a stub receive-only router. The receive-only keyword will restrict the router from sharing any of its routes with any other router in that EIGRP autonomous system. This keyword will also prevent any type of route from being sent.
Therefore we will remove this command and replace it with the eigrp stub command:
R3# configure terminal R3(config)# router eigrp 123 R3(config-router)# no eigrp stub receive-only R3(config-router)# eigrp stub
R3(config-router)# end
Now R3 will send updates containing its connected and summary routes to other routers.
Notice that the eigrp stub command equals to the eigrp stub connected summary because the connected and summary options are enabled by default.
Next we will configure router R3 so that it has only 2 subnets of 10.0.0.0 network. Use the show ip route command on R3 to view its routing table:

Because we want the routing table of R3 only have 2 subnets so we have to summary sub- networks at the interface which is connected with R3, the s0/0 interface of R4.
There is one interesting thing about the output of the show ip route shown above: the
10.2.3.0/24, which is a directly connected network of R3. We can't get rid of it in the routing table no matter what technique we use to summary the networks. Therefore, to make the routing table of R3 has only 2 subnets we have to summary other subnets into one subnet.
In the output if we don't see the summary line (like 10.0.0.0/8 is a summary...) then we should use the command ip summary-address eigrp 123 10.2.0.0 255.255.0.0 so that all the ping can work well.
In conclusion, we will use the ip summary-address eigrp 123 10.2.0.0 255.255.0.0 at the interface s0/0 of R4 to summary.
R4> enable R4# conf t
R4(config)# interface s0/0 R4(config-if)# ip summary-address eigrp 123 10.2.0.0
2 55.255.0.0
Now we jump back to R3 and use the show ip route command to verify the effect, the output is shown below:

Note: Please notice that the IP addresses and the subnet masks in your real exam might be different so you might use different ones to solve this question.
Just for your information, notice that if you use another network than 10.0.0.0/8 to summary, for example, if you use the command ip summary-address eigrp 123 10.2.0.0
255.255.0.0 you will leave a /16 network in the output of the show ip route command.

But in your real exam, if you don't see the line "10.0.0.0/8 is a summary, Null0" then you can summarize using the network 10.2.0.0/16. This summarization is better because all the pings can work well.
Finally don't forget to use the copy run start command on routers R3 and R4 to save the configurations.
R3(config-if)# end
R3# copy run start
R4(config-if)# end
R4# copy run start
If the "copy run start" command doesn't work then use "write memory."