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CTAL-TM-German Praxisprüfung - CTAL-TM-German Zertifikatsdemo, CTAL-TM-German Online Prüfung - FreeTorrent

CTAL-TM-German

Exam Code: CTAL-TM-German

Exam Name: ISTQB Certified Tester Advanced Level - Test Manager (CTAL_TM_001 Deutsch Version)

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
DRAG DROP
You are developing an application that displays a list of race results. The race results are stored in the following class:

The code that manages the list is as follows:

You need to implement the AddRace method.
Match the code segment to its location. (To answer, drag the appropriate code segment from the column on the left to its location on the right. Each code segment may be used once, more than once, or not at all. Each correct match is worth one point.)

Answer:
Explanation:


NEW QUESTION: 2
A security policy is a document or set of documents that describes, at a high level, the security controls that will be implemented by the company. Which one of the following policies forbids everything and restricts usage of company computers, whether it is system usage or network usage?
A. Promiscuous Policy
B. Information-Protection Policy
C. Paranoid Policy
D. Prudent Policy
Answer: C

NEW QUESTION: 3
What are three advantages of index-organized tables? (Choose three.)
A. Fewer I/O operations are needed to retrieve data.
B. Less physical storage space is needed for the data.
C. The table needs to be analyzed less frequently.
D. Data is stored in primary key sequence.
Answer: A,B,D

NEW QUESTION: 4
Which two mechanisms can be used to eliminate Cisco Express Forwarding polarization? (Choose two.)
A. different hashing inputs at each layer of the network
B. Cisco Express Forwarding antipolarization
C. the unique-ID/universal-ID algorithm
D. alternating cost links
Answer: A,C
Explanation:
This document describes how Cisco Express Forwarding (CEF) polarization can cause suboptimal use of redundant paths to a destination network. CEF polarization is the effect when a hash algorithm chooses a particular path and the redundant paths remain completely unused.
How to Avoid CEF Polarization
Alternate between default (SIP and DIP) and full (SIP + DIP + Layer4 ports) hashing inputs configuration at each layer of the network.
Alternate between an even and odd number of ECMP links at each layer of the network.
The CEF load-balancing does not depend on how the protocol routes are inserted in the routing table. Therefore, the
OSPF routes exhibit the same behavior as EIGRP. In a hierarchical network where there are several routers that perform load-sharing in a row, they all use same algorithm to load-share.
The hash algorithm load-balances this way by default:
1: 1
2: 7-8
3: 1-1-1
4: 1-1-1-2
5: 1-1-1-1-1
6: 1-2-2-2-2-2
7: 1-1-1-1-1-1-1
8: 1-1-1-2-2-2-2-2
The number before the colon represents the number of equal-cost paths. The number after the colon represents the proportion of traffic which is forwarded per path.
This means that:
For two equal cost paths, load-sharing is 46.666%-53.333%, not 50%-50%.
For three equal cost paths, load-sharing is 33.33%-33.33%-33.33% (as expected).
For four equal cost paths, load-sharing is 20%-20%-20%-40% and not 25%-25%-25%-25%.
This illustrates that, when there is even number of ECMP links, the traffic is not load-balanced.
Cisco IOS introduced a concept called unique-ID/universal-ID which helps avoid CEF polarization. This algorithm, called the universal algorithm (the default in current Cisco IOS versions), adds a 32-bit router-specific value to the hash function (called the universal ID - this is a randomly generated value at the time of the switch boot up that can can be manually controlled). This seeds the hash function on each router with a unique ID, which ensures that the same source/destination pair hash into a different value on different routers along the path. This process provides a better network-wide load-sharing and circumvents the polarization issue. This unique -ID concept does not work for an even number of equal-cost paths due to a hardware limitation, but it works perfectly for an odd number of equal- cost paths. In order to overcome this problem, Cisco IOS adds one link to the hardware adjacency table when there is an even number of equal-cost paths in order to make the system believe that there is an odd number of equal-cost links.
Reference: http://www.cisco.com/c/en/us/support/docs/ip/express-forwarding-cef/116376-technote-cef-00.html

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