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NEW QUESTION: 1
The characteristics of 802.1X Authentication include (Select three):
A. Port based authentication
B. EAP terminates on authenticator
C. Extensible Authentication Protocol
D. Support of RADIUS external authentication
E. L3 Authentication
Answer: A,C,D

NEW QUESTION: 2

Answer:
Explanation:
Router>enable
Router#config terminal
Router(config)#hostname Apopka
2) Enable-secret password (cisco10):
Apopka(config)#enable secret cisco10
3) Set the console password to RouterPass:
Apopka(config)#line console 0
Apopka(config-line)#password RouterPass
Apopka(config-line)#login
Apopka(config-line)#exit
4) Set the Telnet password to scan90:
Apopka(config)#line vty 0 4
Apopka(config-line)#password scan90
Apopka(config-line)#login
Apopka(config-line)#exit
5) Configure Ethernet interface (on the right) of router Apopka:
The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the formula:
Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32.
Therefore:
Increment: 32
Network address: 209.165.201.0
Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP - 209.165.201.31 - is the broadcast address of the first subnet).
-> The second assignable host address of this subnetwork is 209.165.201.2/27 Assign the second assignable host address to Fa0/0 interface of Apopka router:
Apopka(config)#interface Fa0/0
Apopka(config-if)#ip address 209.165.201.2 255.255.255.224
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
6) Configure Serial interface (on the left) of router Apopka:
Using the same method to find out the increment of the Serial network:
Serial network 192.0.2.128/28:
Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet) Broadcast address: 192.0.2.143
-> The last assignable host address in this subnet is 192.0.2.142/28.
Assign the last assignable host address to S0/0/0 interface of Apopka router:
Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful) Apopka(config-if)#ip address 192.0.2.142 255.255.255.240 Apopka(config-if)#no shutdown Apopka(config-if)#exit
7) Configure RIP v2 routing protocol:
Apopka(config)#router rip
Apopka(config-router)#version 2
Apopka(config-router)#network 209.165.201.0
Apopka(config-router)#network 192.0.2.128
Apopka(config-router)#end
Save the configuration:
Apopka#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!

NEW QUESTION: 3
You are developing a sorting algorithm that uses partitioning and comparison to arrange an array of numbers in the correct order.
You write a method that partitions the array so that the items less than pivot go to the left side, whereas the items greater than pivot go to the right side.
The partitioning method has the following signature:
- static int Partition (int[] numbers, int left,
- int right, int pivotIndex)
Which of the following algorithms should you use to sort the array using the Partition method?
A. static int[] QuickSort(int[] numbers,
int left, int right)
{
if (right > left)
{
int pivotIndex = left + (right - left) / 2;
pivotIndex = Partition(
numbers, left, right, pivotIndex);
QuickSort(
numbers, left, pivotIndex);
QuickSort(
numbers, pivotIndex + 1, right);
}
return numbers;
}
B. static int[] QuickSort(int[] numbers,
int left, int right)
{
if (right > left)
{
int pivotIndex = left + (right - left) / 2;
pivotIndex = Partition(
numbers, left, right, pivotIndex);
QuickSort(
numbers, left, pivotIndex + 1);
QuickSort(
numbers, pivotIndex + 1, right);
}
return numbers;
}
C. static int[] QuickSort(int[] numbers,
int left, int right)
{
if (right > left)
{
int pivotIndex = left + (right - left) / 2;
pivotIndex = Partition(
numbers, left, right, pivotIndex);
QuickSort(
numbers, left, pivotIndex - 1);
QuickSort(
numbers, pivotIndex, right);
}
return numbers;
}
D. static int[] QuickSort(int[] numbers,
int left, int right)
{
if (right > left)
{
int pivotIndex = left + (right - left) / 2;
pivotIndex = Partition(
numbers, left, right, pivotIndex);
QuickSort(
numbers, left, pivotIndex - 1);
QuickSort(
numbers, pivotIndex + 1, right);
}
return numbers;
}
Answer: D