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SUSE Test SCA_SLES15 Vce Free | SCA_SLES15 Valid Dumps Files & SCA_SLES15 Exam Vce - FreeTorrent

SCA_SLES15

Exam Code: SCA_SLES15

Exam Name: SUSE Certified Administrator in Enterprise Linux 15 (050-754)

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
Examine this description of the TRANSACTIONS table:

Which two SQL statements execute successfully? (Choose two.)
A. SELECT customer_id AS 'CUSTOMER-ID', transaction_date AS DATE, amount + 100 'DUES AMOUNT' FROM transactions;
B. SELECT customer_id CUSTID, transaction_date TRANS_DATE, amount + 100 DUES FROM transactions;
C. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS "DATE", amount + 100 DUES FROM transactions;
D. SELECT customer_id AS CUSTOMER-ID, transaction_date AS TRANS_DATE, amount + 100 "DUES AMOUNT" FROM transactions;
E. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS DATE, amount + 100 "DUES" FROM transactions;
Answer: B,C

NEW QUESTION: 2






A. Option C
B. Option D
C. Option B
D. Option A
Answer: A

NEW QUESTION: 3
The perimeter of a rectangle is 136, what is the area of the rectangle?
(1) The length is more than twice the width.
(2) The length and width are both prime numbers larger than 30.
A. Statement (2) BY ITSELF is sufficient to answer the question, but statement (1) by itself is not.
B. Statement (1) BY ITSELF is sufficient to answer the question, but statement (2) by itself is not.
C. Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, even though NEITHER statement BY ITSELF is sufficient.
D. Either statement BY ITSELF is sufficient to answer the question.
E. Statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question, requiring more data pertaining to the problem.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Define L as the length and W as the width.
2L + 2W = 136 ---> L + W = 68. We need one more equation in order to find the area.
Statement (1) does not give you exact values and therefore it's not sufficient.
Statement (2) tells us that both L and W are prime numbers larger than 30, using the equation in the question; the only option to get 68 is with 31 and 37. This statement is sufficient; the area is 31 x 37.

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