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2024 PEGAPCSA85V1 Latest Test Simulator & Test PEGAPCSA85V1 Engine - New Pega Certified System Architect (PCSA) 85V1 Dumps Sheet - FreeTorrent

PEGAPCSA85V1

Exam Code: PEGAPCSA85V1

Exam Name: Pega Certified System Architect (PCSA) 85V1

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
Why would an attacker use a proxy server in front of the exploit server?
A. redundancy if there is a failure of the exploit server
B. to be able to infect more machines than a single server could
C. to reduce bandwidth used by the attack infrastructure and keep loaded pages cached
D. to protect the identity of the exploit server and make it harder to track
Answer: D

NEW QUESTION: 2
You manage an Office 365 tenant. The subscription details for the tenant are displayed in the following screenshot.

Use the drop-down menus to select the answer choice that answers each question.
NOTE: Each correct answer is worth one point.

Answer:
Explanation:

Explanation

Box1:
Skype for Business is included in Office 365 Business Essentials.
SharePoint is not included in Office 365 Business Essentials.
Box 2: Office 365 Business Essentials user maximum is 300 users.
References: https://products.office.com/en/business/compare-office-365-for-business-plans

NEW QUESTION: 3

A. Option B
B. Option D
C. Option A
D. Option C
Answer: B,C,D
Explanation:
https://library.netapp.com/ecmdocs/ECMP1196979/html/man1/na_lun.1.html
The usage for lun create is shown below. Options not in brackets are mandatory.
lun create -s size -t ostype [ -o noreserve ] [ -e space_alloc ] lun_path
This usage of the lun create command should be employed to create a new LUN of given size,
with initiallyzero contents. The LUN is created at the lun_path given. No file should already exist at
the given lun_path. Thedirectory specified in the lun_path must be a qtree root directory.
The size is specified in bytes. Optionally, a number followed by a one-character multiplier suffix
can be used: c(1), w (2), b (512), k (1024), m (k*k), g (k*m), t (m*m).
The size of the created LUN could be larger than the size specified, in order to get an integral
number ofcylinders while reporting the geometry using SAN protocols.
The size of the LUN actually created is reported if it is different from that specified in the
command.
The mandatory ostype argument is one of: solaris (the LUN will be used to store a Solaris raw disk
in a singleslicepartition), windows (the LUN will be used to store a raw disk device in a single-
partition Windows diskusing the MBR (Master Boot Record) partitioning style), hpux (the LUN will
be used to store HP-UX data), aix(the LUN will be used to store AIX data), vld (the LUN contains a
SnapManager VLD), linux (the LUN will beused to store a Linux raw disk without any partition
table), netware (the LUN will be used to store NetWaredata), vmware (the LUN will be used to
store VMware data), windows_gpt (the LUN will be used to storeWindows data using the GPT
(GUID Partition Type) partitioning style), windows_2008 (the LUN will be used tostore Windows
data for Windows 2008 systems), openvms (the LUN will be used to store Open-VMS data),xen
(the LUN will be used to store Xen data), hyper_v (the LUN will be used to store Hyper-V data),
solaris_efi(the LUN will be used to store Solaris_EFI data).
By default, the LUN is space-reserved. To manage space usage manually, -o noreserve can be
specified.
Using this option will create a LUN without any space being reserved. Provisioning threshold
events can beenabled by specifying -e space_alloc option. This option has to be used in
conjunction with -o noreserve.

NEW QUESTION: 4
Which of the following is true about PKI? (Choose two.)
A. When encrypting a message with the public key, only the public key can decrypt it.
B. When encrypting a message with the public key, only the CA can decrypt it.
C. When encrypting a message with the private key, only the public key can decrypt it.
D. When encrypting a message with the private key, only the private key can decrypt it.
E. When encrypting a message with the public key, only the private key can decrypt it.
Answer: C,E
Explanation:
Explanation/Reference:
Explanation:
E: You encrypt data with the private key and decrypt with the public key, though the opposite is much more frequent.
Public-key cryptography, also known as asymmetric cryptography, is a class of cryptographic protocols based on algorithms that require two separate keys, one of which is secret (or private) and one of which is public. Although different, the two parts of this key pair are mathematically linked.
D: In a PKI the sender encrypts the data using the receiver's public key. The receiver decrypts the data using his own private key.
PKI is a two-key, asymmetric system with four main components: certificate authority (CA), registration authority (RA), RSA (the encryption algorithm), and digital certificates. Messages are encrypted with a public key and decrypted with a private key.

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