JN0-351 Visual Cert Test | Juniper Valid JN0-351 Dumps Demo & Reliable JN0-351 Braindumps Ebook - FreeTorrent
Exam Code: JN0-351
Exam Name: Enterprise Routing and Switching, Specialist (JNCIS-ENT)
Version: V22.75
Q & A: 580 Questions and Answers
JN0-351 Free Demo download
About Juniper JN0-351 Exam
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NEW QUESTION: 1
You support Skype for Business Server 2015 servers in your customer's network. The network includes two branches connected with an 8 megabits per second (Mbps) network circuit. The circuit has 1 Mbps of dedicated bandwidth for Skype for Business voice traffic. The network is required to handle 50 peer- to-peer (P2P) calls at a minimum.
Users report that calls between the branches are being dropped, and voice quality is degraded.
Skype for Business audio codecs:
You need to calculate appropriate bandwidth for the P2P call volume required.
What is the minimum dedicated bandwidth that should you allocate?
A. 1.990 Mbps
B. 1.465 Mbps
C. 2.215 Mbps
D. 2.305 Mbps
E. 1.275 Mbps
Answer: B
Explanation:
References:
https://technet.microsoft.com/en-us/library/jj688118(v=ocs.15).aspx
NEW QUESTION: 2
To stop acceleration on a GAiA Security Gateway, enter command:________ .
Answer:
Explanation:
fwaccel off
NEW QUESTION: 3
Which of the following statements regarding the index of Arrays are NOT true?
A. The index is used to access a particular element of an Array.
B. The index ranges from 0 to n-1.
C. The index ranges from 1 to n.
D. A 2-D Array has both a column index and a row index.
Answer: C
NEW QUESTION: 4
Refer to the exhibit.
A network associate has configured OSPF with the command:
City(config-router)# network 192.168.12.64 0.0.0.63 area 0
After completing the configuration, the associate discovers that not all the interfaces are participating in OSPF. Which
three of the interfaces shown in the exhibit will participate in OSPF according to this configuration statement?
(Choose three.)
A. Serial0/1.104
B. Serial0/1.102
C. FastEthernet0 /1
D. Serial0/1.103
E. Serial0/0
F. FastEthernet0 /0
Answer: B,C,E
Explanation:
The "network 192.168.12.64 0.0.0.63" equals to network 192.168.12.64/26. This network has:
Increment: 64 (/26= 1111 1111.1111 1111.1111 1111.1100 0000)
Network address: 192.168.12.64
Broadcast address: 192.168.12.127
Therefore all interface in the range of this network will join OSPF - B C D are correct.
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