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NEW QUESTION: 1
ネットワークにはcontoso.comという名前のActive Directoryドメインが含まれています。 ドメインには、次の表に示すように構成されたサーバーが含まれています。

すべてのサーバーはWindows Server 2016を実行します。すべてのクライアントコンピューターはWindows 10を実行し、ドメインメンバーです。
すべてのラップトップは、BitLockerドライブ暗号化（BitLocker）を使用して保護されています。アプリケーションサーバーのコンピューターアカウントを含むOU1という名前の組織単位（OU）があります。
OU2という名前のOUには、マーケティング部門のコンピューターのコンピューターアカウントが含まれています。
GP1という名前のグループポリシーオブジェクト（GPO）がOU1にリンクされています。
GP2という名前のGPOがOU2にリンクされています。
すべてのコンピュータはServer1から更新を受け取ります。
Update1という名前の更新規則を作成します。
暗号化ファイルシステム（EFS）データ回復証明書を作成し、その証明書をEFSデータ回復エージェントとしてServer 5に追加する必要があります。
あなたはServer5で何を使うべきですか？ 回答するには、回答領域で適切なオプションを選択します。

Answer:
Explanation:

Explanation:
https://docs.microsoft.com/en-us/windows/threat-protection/windows-information-protection/create-and-verifyan-efs-dra-certificatecipher /R

NEW QUESTION: 2
Was ist der Unterschied zwischen Medienkennzeichnung und Medienkennzeichnung?
A. Die Medienkennzeichnung bezieht sich auf die Verwendung von für Menschen lesbaren Sicherheitsattributen, während sich die Medienkennzeichnung auf die Verwendung von Sicherheitsattributen in internen Datenstrukturen bezieht.
B. Die Medienkennzeichnung bezieht sich auf Sicherheitsattribute, die von der öffentlichen Ordnung / Gesetzgebung gefordert werden, während sich die Medienkennzeichnung auf Sicherheitsattribute bezieht, die von der internen Organisationsrichtlinie gefordert werden.
C. Die Medienkennzeichnung bezieht sich auf die Verwendung von für Menschen lesbaren Sicherheitsattributen, während sich die Medienkennzeichnung auf die Verwendung von Sicherheitsattributen in internen Datenstrukturen bezieht.
D. Die Medienkennzeichnung bezieht sich auf Sicherheitsmerkmale, die von der öffentlichen Ordnung / Gesetzgebung gefordert werden, während sich die Medienkennzeichnung auf die Sicherheit bezieht, die von der internen Organisationsrichtlinie gefordert wird.
Answer: A

NEW QUESTION: 3
Which assignment will lead to a conversion error?
A. A type C data object with the value '1.50E4' to a type I data object
DATA. gv_c(6) TYPE c VALUE '1.50E4', gv_i TYPE i. gv_i = gv_c.
B. An XSTRING type data object to a STRING type data object
DATA. gv_xstring TYPE xstring, gv_string TYPE string. gv_xstring = 'AF00'. gv_string =
gv_xstring.
C. A type P data object to a type F data object
DATA. gv_p TYPE p VALUE '15000', gv_f TYPE f. gv_f = gv_p.
D. A type C data object with the value '123' to a type C data object with length 2
DATA. gv_c3(3) TYPE c VALUE '123', gv_c2(2) TYPE c. gv_c2 = gv_c3.
Answer: A

NEW QUESTION: 4
Which statement describes dynamic routing correctly?
A. easier to configure than static route
B. built for small networks
C. more secure than static
D. high scaling for large network
Answer: D