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2024 JN0-252 Instant Download | New JN0-252 Dumps Book & Mist AI, Associate (JNCIA-MistAI) Exam Cram Review - FreeTorrent

JN0-252

Exam Code: JN0-252

Exam Name: Mist AI, Associate (JNCIA-MistAI)

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
Which one of the following statements about material non-public information is incorrect?
A. Restricting personal and proprietary trading will assist members in complying with the abovementioned standard of professional conduct.
B. An analyst will violate the above mentioned standard of professional conduct if he makes use of the
"mosaic theory".
C. A member may create and use material non-public information as long as the information is either constructed together from publicly available information, or constructed together from non-material information.
Answer: B
Explanation:
Insider trading should not result when a perceptive analyst reaches a conclusion about a corporate action through analysis of public information and items of non-material non-public information
(that is, a "mosaic" of information).

NEW QUESTION: 2
Your network contains two servers named Server1 and Server2 that run Windows Server 2012 R2.
Both servers have the Hyper-V server role installed.
The servers have the hardware configurations shown in the following table.

Server1 hosts five virtual machines that run Windows Server 2012 R2.
You need to move the virtual machines from Server1 to Server2.
The solution must minimize downtime.
What should you do for each virtual machine?
A. Perform a live migration.
B. Perform a quick migration.
C. Perform a storage migration.
D. Export the virtual machines from Server1 and import the virtual machines to Server2.
Answer: D
Explanation:
Explanation
None of these migration options will work between different Processors ( AMD/Intel). The only option remaining is to export and re-import the VMs

NEW QUESTION: 3

A. UPDATE Products SET Price = Price * 1.05
OUTPUT inserted.ProductCode, deleted.Price, inserted.Price
INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
B. UPDATE Products SET Price = Price * 1.05
INSERT INTO ProductsPriceLog (ProductCode, CldPnce, NewPrice;
SELECT ProductCode, Price, Price * 1.05 FROM Products
C. UPDATE Products SET Price = Price * 1.05
OUTPUT inserted.ProductCode, inserted.Price, deleted.Price
INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
D. UPDATE Products SET Price = Price * 1.05
OUTPUT inserted.ProductCode, deleted.Price, inserted.Price *
INTO ProductsPriceLog(ProductCode, OldPrice, NewPrice)
Answer: A

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