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HPE7-IN14

Exam Code: HPE7-IN14

Exam Name: Instructor - HPE Networking Campus Access Architect Expert Written Exam

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
FortiAnalyzerでは、ワイルドカード管理者アカウントとは何ですか?
A. FortiAuthenticatorの任意のユーザーアカウントに対して検証するアカウント
B. ゲストアクセスを読み取り専用権限で許可するアカウント
C. LDAPグループのメンバーへのアクセスを許可するアカウント
D. 2要素認証を必要とするアカウント
Answer: A

NEW QUESTION: 2
企業には、単一の共有AWSアカウントで作業する複数の開発グループがあります。グループのシニアマネージャーは、リソースの作成がアカウントのサービス制限に近づいたときに、サードパーティのAPI呼び出しを通じてアラートを受け取りたいと考えています。
最小限の開発努力でこれを達成するソリューションはどれですか?
A. 定期的に実行されるAWS Configカスタムルールを追加し、AWSサービス制限ステータスをチェックして、通知をAmazon SNSトピックにストリーミングします。シニアマネージャーに通知するAWS Lambda関数をデプロイし、Lambda関数をSNSトピックにサブスクライブします。
B. AWS Personal Health Dashboardチェックを更新するAWS Lambda関数をデプロイし、Lambda関数を定期的に実行するようにAmazon CloudWatchイベントルールを設定します。 Personal Health DashboardイベントとターゲットLambda関数に一致するイベントパターンを使用して、別のCloudWatchイベントルールを作成します。ターゲットのLambda関数で、シニアマネージャーに通知します。
C. 定期的に実行され、AWS Lambda関数をターゲットとするAmazon CloudWatchイベントルールを作成します。
Lambda関数内で、AWS環境の現在の状態を評価し、デプロイされたリソース値をアカウントのリソース制限と比較します。アカウントがサービス制限に近づいている場合は、シニアマネージャーに通知します。
D. AWS Trusted Advisorチェックを更新するAWS Lambda関数をデプロイし、Amazon CloudWatchイベントルールを設定してLambda関数を定期的に実行します。 Trusted AdvisorイベントとターゲットLambda関数に一致するイベントパターンを使用して、別のCloudWatchイベントルールを作成します。ターゲットのLambda関数で、シニアマネージャーに通知します。
Answer: A

NEW QUESTION: 3
Examine the following PL/SQL block: DECLARE
my_plans pls_integer;
BEGIN
my_plans := DBMS_SPM.LOAD_PLANS_FROM_CURSOR_CACHE (sql_id => ?9twu5t2dn5xd?;
END;
Which statement is true about the plan being loaded into the SQL plan baseline by the above command?
A. It is not loaded with the ENABLED status.
B. It is loaded with the ACCEPTED status.
C. It is loaded with the FIXED status.
D. It is not loaded with the ACCEPTED status.
Answer: B

NEW QUESTION: 4
Note: This question is part of a series of questions that use the same or similar answer choices.
An answer choice may be correct for more than one question in the series.
Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:

You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
B. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
C. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo L.CustNoWHERE D.CustNo IS NULL
F. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
G. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: B
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

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