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Exam Code: HPE7-A13
Exam Name: HPE Networking Campus Access Architect Expert Written Exam
Version: V22.75
Q & A: 580 Questions and Answers
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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:
You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
B. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
C. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
D. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
H. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
Answer: G
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php
NEW QUESTION: 2
In order to generate reports in Symantec Control Compliance Suite 9.0 (CCS 9.0), where must the Crystal Reports 2008 Engine be installed?
A. the server that hosts the CCS 9.0 console
B. all Data Processing Service computers
C. the application server that manages the reporting jobs
D. the Data Processing Service computer configured with the Reporter role
Answer: D
NEW QUESTION: 3
Whats the gateway en the global configuration (Choose Three)
Router(config)#ip route vrf blue 0.0.0.0 0.0.0.0 192.168.1.1
Router(config)#ip route vrf red 0.0.0.0 0.0.0.0 192.168.1.2
A. If you type "show ip route vrf blue" you will see "192.168.1.2 as gateway of last resort".
B. If you type "show ip route vrf blue" you will see "192.168.1.1 as gateway of last resort".
C. If you type "show ip route vrf red" you will see "192.168.1.1 as gateway of last resort".
D. Global routing table does not overlap with VRF routing tables.
E. If you type "show ip route" you will see "Gateway of last resort it not set".
Answer: B,D,E
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