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NEW QUESTION: 1
To limit strategic risk management should ensure proper balance between the:
A. Mortgage company's willingness to accept risk and its supporting resources and control
B. Managerial capacities and capabilities and delivery networks
C. Internal operations and possibility of litigation
D. All of these
Answer: A

NEW QUESTION: 2
Which document contains the preliminary description of the business functionality desired by the project sponsor?
A. Requirement Document
B. PMP
C. Project Scope Statement
D. Preliminary Scope Statement
Answer: D

NEW QUESTION: 3
Sara, a security architect, has developed a framework in which several authentication servers work together to increase processing power for an application. Which of the following does this represent?
A. RAID
B. Clustering
C. Warm site
D. Load balancing
Answer: B
Explanation:
Anytime you connect multiple computers to work/act together as a single server, it is known as
clustering. Clustered systems utilize parallel processing (improving performance and availability)
and add redundancy.
Server clustering is used to provide failover capabilities / redundancy in addition to scalability as
demand increases.

NEW QUESTION: 4
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()
OVER (PARTITION BY CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY OrderAmount DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) DESC) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1
Incorrect Answers:
B: The ascending (ASC) sorting would produce the country from which each customer has placed the least orders.
C: We are interested in the number of the orders, not the amount of the orders. We should use ORDER BY COUNT(OrderAmount), not ORDER BY OrderAmount.
D: We are only interested in one single post, only the country from which each customer has placed the most orders. Need to use a WHERE statement (here Where o.Rnk =1 ).