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NEW QUESTION: 1
Given the code fragment:
System.out.printIn("Result: " + 2 + 3 + 5);
System.out.printIn("Result: " + 2 + 3 * 5);
What is the result?
A. Result: 215
Result: 215
B. Result: 10
Result: 30
C. Result: 235
Result: 215
D. Compilation fails
E. Result: 10
Result: 25
Answer: C
Explanation:
Explanation/Reference:
Explanation:
First line:
System.out.println("Result: " + 2 + 3 + 5);
String concatenation is produced.
Second line:
System.out.println("Result: " + 2 + 3 * 5);
3*5 is calculated to 15 and is appended to string 2. Result 215.
The output is:
Result: 235
Result: 215
Note #1:
To produce an arithmetic result, the following code would have to be used:
System.out.println("Result: " + (2 + 3 + 5));
System.out.println("Result: " + (2 + 1 * 5));
run:
Result: 10
Result: 7
Note #2:
If the code was as follows:
System.out.println("Result: " + 2 + 3 + 5");
System.out.println("Result: " + 2 + 1 * 5");
The compilation would fail. There is an unclosed string literal, 5", on each line.

NEW QUESTION: 2
管理者が安全なワイヤレスネットワークをセットアップしています。管理者はサポートすることにしました
WPA2事前共有キーを使用した802.11nおよび802.11g。ユーザーには事前共有キー付きのSSIDが提供されますが、管理者はSSIDブロードキャストとMACフィルタリングを無効にしています。一部のユーザーが接続の問題を報告しています。ユーザーの接続の問題を解決する可能性が最も高いのは次のどれですか？
A. MACフィルタリングを有効にします。
B. SSIDブロードキャストを有効にします。
C. WEP 128ビットキーを使用します。
D. デバイスを802.11nのみに制限します。
Answer: B

NEW QUESTION: 3
構成管理の主要なレコードタイプは何ですか？
A. ビジネスサービスおよび構成アイテム（CI）
B. 関係タイプと構成アイテム（CI）
C. 資産アイテム（AI）と関係タイプ
D. アセットアイテム（AI）と構成アイテム（CI）
Answer: B