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NEW QUESTION: 1
Mark works as a Network Administrator for NetTech Inc. The company has a Windows 2000 domain-based network. Users report that they are unable to log on to the network. Mark finds that accounts are locked out due to multiple incorrect log on attempts. What is the most likely cause of the account lockouts?
A. Brute force attack
B. Spoofing
C. PING attack
D. SYN attack
Answer: A
Explanation:
Brute force attack is the most likely cause of the account lockouts. In a brute force attack, unauthorized users attempt to log on to a network or a computer by using multiple possible user names and passwords. Windows 2000 and other network operating systems have a security feature that locks a user account if the number of failed logon attempts occur within a specified period of time, based on the security policy lockout settings. Answer A is incorrect. Spoofing is a technique that makes a transmission appear to have come from an authentic source by forging the IP address, email address, caller ID, etc. In IP spoofing, a hacker modifies packet headers by using someone else's IP address to hide his identity. However, spoofing cannot be used while surfing the Internet, chatting on-line, etc. because forging the source IP address causes the responses to be misdirected. Answer C is incorrect. A SYN attack affects computers running on the TCP/IP protocol. It is a protocol-level attack that can render a computer's network services unavailable. A SYN attack is also known as SYN flooding. Answer D is incorrect. When a computer repeatedly sends ICMP echo requests to another computer, it is known as a PING attack.

NEW QUESTION: 2
When does 802.1X authentication of a wireless station occur?
A. It occurs after the 802.11 authentication process, but before the 802.11 association process.
B. It occurs after the 802.11 association process, but before the 802.11 authentication process.
C. It occurs in place of the 802.11 authentication process.
D. It occurs after the 802.11 association process.
Answer: D

NEW QUESTION: 3
ユーザーがエンゲージメントスタジオを一時停止し、見込み客がまだ待機時間を残している場合、どうなるでしょうか。
A. 待機時間が一時停止し、プログラムが再開して見込み客がrema.n.ngの待機時間を終了し、次のステップに進みます。
B. 待ち時間は引き続き処理され、プロスペクトはプログラムが再開するとすぐに次のステップに進みます。
C. 待機時間が処理され続け、残りの待機時間が満たされると、見込み客はすぐに次のステップに処理します。
D. wait.meは一時停止され、プログラムが再開すると、プロスペクトはすぐに次のステップに進みます。
Answer: A

NEW QUESTION: 4
コードの断片を考えると：
interface CourseFilter extends Predicate<String> {
public default boolean test (String str) {
return str.contains ("Java");
}
}
and
List<String> strs = Arrays.asList("Java", "Java EE", "Embedded Java");
Predicate<String> cf1 = s - > s.length() > 3;
Predicate cf2 = new CourseFilter() { //line n1
public boolean test (String s) {
return s.startsWith ("Java");
}
};
long c = strs.stream()
.filter(cf1)
.filter(cf2//line n2
.count();
System.out.println(c);
結果は何ですか？
A. 0
B. 1
C. 行n1でコンパイルエラーが発生します。
D. コンパイルエラーが行n2で発生します。
Answer: D