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NEW QUESTION: 1
Regarding the processing of the WLAN dual-system hot standby to the server, the following statement is correct?
A. In the load balancing scenario, the active and standby ACs interact with the server.
B. VRRP hot standby scenario, the active and standby ACs can send VIP/VMAC to the server, and both devices use VIP to interact with the server.
C. VRRP hot standby scenario, the active and standby ACs can advertise VIP/VMAC to the server. Only one device uses VIP to interact with the server.
D. In a load balancing scenario, only one AC interacts with the server.
Answer: A,C

NEW QUESTION: 2





A. Option D
B. Option B
C. Option A
D. Option C
Answer: C
Explanation:
Explanation
The exhibit shows the default gateway address to be that of LAN1. This should be changed to the LAN2 gateway address to allow client computers access on LAN2.
In general, the first and last addresses in a subnet are used as the network identifier and broadcast address, respectively. All other addresses in the subnet can be assigned to hosts on that subnet. For example, IP addresses of networks with subnet masks of at least 24 bits ending in .0 or .255 can never be assigned to hosts.
Such "last" addresses of a subnet are considered "broadcast" addresses and all hosts on the corresponding subnet will respond to it. Theoretically, there could be situations where you can assign an address ending in .0:
for example, if you have a subnet like 192.168.0.0/255.255.0.0, you are allowed to assign a host the address
192.168.1.0. It could create confusion though, so it's not a very common practice.
Example10.6.43.0 with subnet 255.255.252.0 (22 bit subnet mask) means subnet ID 10.6.40.0, a host address range from 10.6.40.1 to 10.6.43.254 and a broadcast address10.6.43.255. So in theory, your example 10.6.43.0 would be allowed as a valid host address. The default gateway address should not end in .0 with the /24 address.
References:
Training Guide: Installing and Configuring Windows Server 2012 R2, Chapter 4: Deploying domain controllers, Lesson 4: Configuring IPv6/IPv4 Interoperability, p. 254-256

NEW QUESTION: 3
Which routing protocol cannot be run over an Ipipe?
A. BGP
B. IS-IS
C. RIP
D. OSPF
Answer: B

NEW QUESTION: 4
EIGRP OTP実装でのLISPカプセル化について正しい説明はどれですか。
A. OTPはLISPコントロールプレーンを維持します
B. LISPはネクストホップを学習します
C. OTPはLISPカプセル化を使用してネイバーからルートを取得します
D. OTPは動的マルチポイントトンネリングにLISPカプセル化を使用します
Answer: A
Explanation:
Explanation
The EIGRP Over the Top solution can be used to ensure connectivity between disparate EIGRP sites. This feature uses EIGRP on the control plane and Locator ID Separation Protocol (LISP) encapsulation on the data plane to route traffic across the underlying WAN architecture. EIGRP is used to distribute routes between customer edge (CE) devices within the network, and the traffic forwarded across the WAN architecture is LISP encapsulated.
EIGRP OTP only uses LISP for the data plane, EIGRP is still used for the control plane. Therefore we cannot say OTP uses LISP encapsulation for dynamic multipoint tunneling as this requires encapsulating both data and control plane traffic -> Answer 'OTP uses LISP encapsulation for dynamic multipoint tunneling' is not correct.
In OTP, EIGRP serves as the replacement for LISP control plane protocols (therefore EIGRP will learn the next hop, not LISP -> Answer 'LISP learns the next hop' is not correct). Instead of doing dynamic EID-to-RLOC mappings in native LISP-mapping services, EIGRP routers running OTP over a service provider cloud create targeted sessions, use the IP addresses provided by the service provider as RLOCs, and exchange routes as EIDs. Let's take an example:

If R1 and R2 ran OTP to each other, R1 would learn about the network 10.0.2.0/24 from R2 through EIGRP, treat the prefix 10.0.2.0/24 as an EID prefix, and take the advertising next hop
198.51.100.62 as the RLOC for this EID prefix. Similarly, R2 would learn from R1 about the network 10.0.1.0/24 through EIGRP, treat the prefix 10.0.1.0/24 as an EID prefix, and take the advertising next hop 192.0.2.31 as the RLOC for this EID prefix. On both routers, this information would be used to populate the LISP mapping tables. Whenever a packet from 10.0.1.0/24 to
10.0.2.0/24 would arrive at R1, it would use its LISP mapping tables just like in ordinary LISP to discover that the packet has to be LISP encapsulated and tunneled toward 198.51.100.62, and vice versa. The LISP data plane is reused in OTP and does not change; however, the native LISP mapping and resolving mechanisms are replaced by EIGRP.
Reference: CCIE Routing and Switching V5.0 Official Cert Guide, Volume 1, Fifth Edition