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Latest C_ARCON_2308 Exam Cost - New C_ARCON_2308 Dumps Files, C_ARCON_2308 Well Prep - FreeTorrent

C_ARCON_2308

Exam Code: C_ARCON_2308

Exam Name: SAP Certified Application Associate - SAP Ariba Contracts

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, bei denen die gleichen oder ähnliche Antwortmöglichkeiten verwendet werden. Eine Antwortauswahl kann für mehr als eine Frage in der Reihe richtig sein. Jede Frage ist unabhängig von den anderen Fragen in dieser Reihe. In einer Frage angegebene Informationen und Details gelten für diese Frage.
Sie haben eine Datenbank für ein Bankensystem. Die Datenbank enthält zwei Tabellen mit den Namen tblDepositAcct und tblLoanAcct, in denen Einlagen- und Darlehenskonten gespeichert sind. Beide Tabellen enthalten die folgenden Spalten:

Sie müssen eine Abfrage ausführen, um die Gesamtzahl der Kunden zu ermitteln, die sowohl Einzahlungs- als auch Darlehenskonten haben.
Welche Transact-SQL-Anweisung sollten Sie ausführen?
A. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT (*) FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
C. SELECT COUNT (*) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
D. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT L.CustNo) VON tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
F. SELECT COUNT (DISTINCT COALESCE (D.CustNo, L.CustNo)) FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWhere
G. SELECT COUNT (DISTINCT D.CustNo) FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
H. SELECT COUNT (*) FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: B
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 2
An organization has 500 mailboxes enabled for Virtual Vault. An administrator needs to modify the number of Vault Cache users that can be updated concurrently. Where must the administrator make the modification?
A. in the IIS, EnterpriseVault Virtual Directory properties
B. in the Advanced tab of the Desktop policy
C. in the IIS, EnterpriseVault Virtual Directory, GetSlotWithServer.aspx properties
D. in the Enterprise Vault Server properties
Answer: D

NEW QUESTION: 3
The following grid shows the state of a 2D array:

This grid is created with the following code:

Which line of code, when inserted in place of //line n1, adds an X into the grid so that the grid contains three consecutive X's?
A. grid[0][2] = 'X';
B. grid[1][2] = 'X';
C. grid[3][1] = 'X';
D. grid[1][3] = 'X';
E. grid[2][0] = 'X';
Answer: A
Explanation:
Explanation/Reference:

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