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NEW QUESTION: 1
Which of the following statements about access lists are true? (Choose three.)
A. Standard access lists filter on the destination address
B. Extended access lists should be placed as near as possible to the destination
C. Extended access lists should be placed as near as possible to the source
D. Standard access lists should be placed as near as possible to the source
E. Standard access lists filter on the source address
F. Standard access lists should be placed as near as possible to the destination
Answer: C,E,F
Explanation:
Explanation/Reference:
Explanation:
Standard ACLs
A standard IP ACL is simple; it filters based on source address only. You can filter a source network or a source host, but you cannot filter based on the destination of a packet, the particular protocol being used such as the Transmission Control Protocol (TCP) or the User Datagram Protocol (UDP), or on the port number. You can permit or deny only source traffic.
Extended ACLs:
An extended ACL gives you much more power than just a standard ACL. Extended IP ACLs check both the source and destination packet addresses. They can also check for specific protocols, port numbers, and other parameters, which allow administrators more flexibility and control.
Named ACLs
One of the disadvantages of using IP standard and IP extended ACLs is that you reference them by number, which is not too descriptive of its use. With a named ACL, this is not the case because you can name your ACL with a descriptive name. The ACL named DenyMike is a lot more meaningful than an ACL simply numbered 1. There are both IP standard and IP extended named ACLs.
Another advantage to named ACLs is that they allow you to remove individual lines out of an ACL. With numbered ACLs, you cannot delete individual statements. Instead, you will need to delete your existing access list and re-create the entire list.
Reference: http://computernetworkingnotes.com/network-security-access-lists-standards-and-extended/ access-control-list.html

NEW QUESTION: 2
A customer needs two client IBM i partitions on a 4-core Power 720, with storage hosted by VIO Server. What is the least expensive method to manage this environment?
A. Integrated Virtualization Manager
B. Virtual Partition Manager
C. Systems Director Navigator for PowerVM
D. HMC
Answer: A

NEW QUESTION: 3
Tableauの__________________を使用して、データをクリーンアップ/整理できます。
A. データオーガナイザー
B. データインタプリタ
C. データマネージャー
D. データクリーナー
Answer: B
Explanation:
Explanation
When you track data in Excel spreadsheets, you create them with the human interface in mind. To make your spreadsheets easy to read, you might include things like titles, stacked headers, notes, maybe empty rows and columns to add white space, and you probably have multiple tabs of data too.
When you want to analyze this data in Tableau, these aesthetically pleasing attributes make it very difficult for Tableau to interpret your data. That's where Data Interpreter can help.

NEW QUESTION: 4
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)

You need to display rows from the Orders table for the Customers row having the Customerld value set to 1 in the following XML format.

Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers. CustomerId = 1 FOR XML RAW, ELEMENTS
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers. CustomerId = 1 FOR XML AUTO
C. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers. CustomerId = 1 FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId -Customers.CustomerId WHERE Customers. CustomerId= 1 FOR XML AUTO, ELEMENTS
E. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML PATH ('Customers')
F. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers. CustomerId = 1 FOR XML AUTO, ELEMENTS
G. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers-CustomerId WHERE Customers. CustomerId = 1 FOR XML RAW
H. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId= 1 FOR XML PATH ('Customers')
Answer: H
Explanation:
--Burgos - NO
Verified answer as correct.