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NEW QUESTION: 1
Refer to the exhibit.

The exhibit shows the current plan for a wired network upgrade.
As much as possible, the customer wants to flatten the architecture and avoid recabling. However, each Building 2 switch must also maintain connectivity to the core if one link fails. What should the architect propose to meet the customer requirements?
A. Extend additional fiber between the buildings so that each Building 2 switch can have a direct 10 GbE connection to the core.
B. Connect each Building 2 switch directly to the core on a single fiber strand through the use of SFP+-SR transceivers.
C. Use two additional 2930F switches to act as an aggregation layer for Building 2; connect them to the core on 40 GbE connections.
D. Combine the switches in each Building 2 closet as a VSF fabric; establish two 10 GbE connections to the core per fabric.
Answer: D

NEW QUESTION: 2

CREATE MASTER KEY ENCRYPTION BY PASSWORD = 'MyPassword1!'
CREATE CERTIFICATE TDE_Certificate WITH SUBJECT = 'TDE Certificate';
BACKUP CERTIFICATE TDE_Certificate TO FILE = ''d:\TDE_Certificate.cer'
WITH PRIVATE KEY (FILE = 'D:\TDE_Certificate.key', ENCRYPTION BY PASSWORD
'MyPassword1!');
CREATE DATABASE ENCRYPTION KEY
WITH ALGORITHM = AES_256
ENCRYPTION BY SERVER CERTIFICATE TDE_Certificate;
ALTER DATABASE Orders SET ENCRYPTION ON;

A. CREATE CERTIFICATE TDE_CertificateWITH SUBJECT = 'TDE Certificate';USE Orders;CREATE DATABASE ENCRYPTION KEYWITH ALGORITHM = AES_256ENCRYPTION BY SERVER CERTIFICATE TDE_Certificate;
B. CREATE CERTIFICATE TDE_CertificateFROM FILE = 'd:\TDE_Certificate.cer';
C. ALTER DATABASE MasterSET ENCRYPTION OFF;
D. CREATE CERTIFICATE TDE_CertificateFROM FILE = 'd:\TDE_Certificate.cer'WITH PRIVATE KEY (FILE = 'D:\TDE_Certificate.key',DECRYPTION BY PASSWORD
'MyPassword1!');
Answer: D

NEW QUESTION: 3
展示を表示して、EMPLOYEESテーブルの構造を調べます。

MANAGER_IDが管理する100人の従業員とそのマネージャーを選択するとします。
2つの列に出力が必要です。最初の列には従業員のマネージャーのLAST_NAMEが含まれ、2番目の列には従業員のLAST_NAMEが含まれる必要があります。
どのSQLステートメントを実行しますか？
A. SELECT m.last_name "Manager"、e.last_name "Employee" FROM従業員m JOIN従業員eWHERE m.employee_id = e.manager_id AND e.manager_id = 100
B. SELECT m.last_name "Manager"、e.last_name "Employee" FROM従業員m JOIN従業員eON m.employee_id = e.manager_idWHERE m.manager_id = 100;
C. SELECT m.last_name "Manager"、e.last_name "Employee" FROM従業員m JOIN従業員eON m.employee_id = e.manager_idWHERE e.manager_id = 100;
D. SELECT m.last_name "Manager"、e.last_name "Employee" FROM従業員m JOIN従業員eON e.employee_id = m.manager_idWHERE m.manager_id = 100;
Answer: C