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Exam Code: CDPSE
Exam Name: Certified Data Privacy Solutions Engineer
Version: V22.75
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NEW QUESTION: 1
You own a home network connecting through an always-on connection and need to assign IPv6 addresses to your routers because you want to follow the guidelines spelled out in RFC 3177. You want to design your network with the correct prefixes.
Which prefix would your ISP likely allocate to your network?
A. 64-bit prefix
B. 47-bit prefix
C. 128-bit prefix
D. 48-bit prefix
Answer: D
Explanation:
Explanation/Reference:
From RFC 3177: This document provides recommendations to the addressing registries (APNIC, ARIN and RIPE-NCC) on policies for assigning IPv6 address blocks to end sites. In particular, it recommends the assignment of /48 in the general case, /64 when it is known that one and only one subnet is needed and /128 when it is absolutely known that one and only one device is connecting.
NEW QUESTION: 2
Welches der folgenden Ziele ist KEIN Ziel des Serviceübergangs?
A. Planen und Verwalten der Kapazitäts- und Ressourcenanforderungen zum Verwalten einer Version
B. Schulung und Zertifizierung im Projektmanagement
C. Bereitstellung von qualitativ hochwertigem Wissen und Informationen zu Diensten und Service-Assets
D. Um sicherzustellen, dass ein Dienst verwaltet, betrieben und unterstützt werden kann
Answer: B
NEW QUESTION: 3
A router is connected to an HDLC circuit via a T1 physical interface. The SLA for this link only allows for a sustained rate of 768 kb/s. Bursts are allowed for up to 30 seconds at up to line rate, with a window Tc of 125 ms. What should the Bc and Be setting be when using generic traffic shaping?
A. Be = , 0 Be = 96000
B. Be = 46320000 , Bc = 96000
C. Be = , 768000 Be = 32000
D. Be = , 128000 Be = 7680
Answer: B
Explanation:
Tc= 125 CIR = 768 What is the Be
T1 = 1.544 Mbps Bursts are allowed for 30 seconds Seconds * Bandwidth in bps = Be 30 * 1544000 = Be 30 * 1544000 = 46320000 Be = 46320000 What is Bc? Bc = Tc * CIR Bc = 125 * 768 Bc = 96000 Traffic Shaping Parameters We can use the following traffic shaping parameters: CIR = committed information rate (= mean time) EIR = excess information rate TB = token bucket (= Bc + Be) Bc = committed burst size (= sustained burst size) Be = excess burst size DE = discard eligibility Tc = measurement interval AR = access rate corresponding to the rate of the physical interface (so if you use a T1, the AR is approximately 1.5 Mbps).
Committed Burst Size (Bc) The maximum committed amount of data you can offer to the network is defined as Bc. Bc is a measure for the volume of data for which the network guarantees message delivery under normal conditions. It is measured during the committed rate Tc. Excess Burst Size (Be) The number of noncommitted bits (outside of CIR) that are still accepted by the Frame Relay switch but are marked as eligible to be discarded (DE). The token bucket is a 'virtual' buffer. It contains a number of tokens, enabling you to send a limited amount of data per time interval. The token bucket is filled with Bc bits per Tc.
The maximum size of the bucket is Bc + Be. If the Be is very big and, if at T0 the bucket is filled with Bc + Be tokens, you can send Bc + Be bits at the access rate. This is not limited by Tc but by the time it takes to send the Be. This is a function of the access rate. Committed Information Rate (CIR) The CIR is the allowed amount of data which the network is committed to transfer under normal conditions. The rate is averaged over a increment of time Tc. The CIR is also referred to as the minimum acceptable throughput. Bc and Be are expressed in bits, Tc in seconds, and the access rate and CIR in bits per second. Bc, Be, Tc and CIR are defined per datalink connection identifier (DLCI). Due to this, the token
bucket filter controls the rate per DLCI. The access rate is valid per usernetwork interface. For Bc,
Be and CIR incoming and outgoing values can be distinguished. If the connection is symmetrical,
the values in both directions are the same. For permanent virtual circuits, we define incoming and
outgoing Bc, Be and CIR at subscription time.
Peak = DLCI's maximum speed. The bandwidth for that particular DLCI.
Tc = Bc / CIR
Peak = CIR + Be/Tc = CIR (1 + Be/Bc)
If the Tc is one second then:
Peak = CIR + Be = Bc + Be
Reference
http://www.cisco.com/warp/public/125/21.pdf
NEW QUESTION: 4
A. Option B
B. Option C
C. Option A
D. Option E
E. Option D
Answer: B
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