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NEW QUESTION: 1
Which of the following components of CPU handles logarithms or trigonometric calculations?
A. PFU
B. ALU
C. FPU
D. CU
Answer: C

NEW QUESTION: 2
A user authenticating with Amazon Cognito will go through a multi-step process to bootstrap their
credentials. Amazon Cognito has two different flows for authentication with public providers. Which of the
following are the two flows?
A. Authenticated and non-authenticated
B. Enhanced and basic
C. Single step and multistep
D. Public and private
Answer: B
Explanation:
A user authenticating with Amazon Cognito will go through a multi-step process to bootstrap their
credentials. Amazon Cognito has two different flows for authentication with public providers: enhanced
and basic.
Reference: http://docs.aws.amazon.com/cognito/devguide/identity/concepts/authentication-flow/

NEW QUESTION: 3
An application developer needs to access Worklight server properties that are defined in the worklight.properties file.
Which of the following method definitions will enable the application developer to access the local.IPAddress property?
A. WL.Server.getConfiguration("local.IPAddress")
B. WL.Server.Configuration["local.IPAddress"]
C. WL.Server.configuration.local.IPAddress
D. WL.Server.invokeConfiguration("local.IPAddress")
Answer: B
Explanation:
Object WL.Server.configuration
A map that contains all the server properties that are defined in the file worklight.properties.
Syntax
WL.Server.configuration ["property-name"]
WL.Server.configuration.property-name
Both syntaxes are equivalent. When the property name contains a period ('.'), for example
local.IPAddress, the array index syntax must be used.
Example
var addr = WL.Server.configuration["local.IPAddress"];
References:
https://www.ibm.com/support/knowledgecenter/SSZH4A_6.0.0/com.ibm.worklight.help.doc/
apiref/ r_object_wl_server_configuration.html

NEW QUESTION: 4
展示を参照してください。

エンジニアは、アトランタとワシントンのサイトを指す州道でニューヨークのルーターを構成しました。アトランタとワシントンのルーターでコマンドを構成して、両方のサイトがニューヨークのルーターのloopback2インターフェイスに到達できるようにする必要があるのはいつですか。
A. ipv6 route 0/0 Serial 0/0/0
B. ipv6 route ::/0 2000::2
C. ipv6 route ::/0 Serial 0/0/0
D. ip route 0.0.0.0.0.0.0.0 Serial 0/0/0
E. ipv6 route ::/0 Serial 0/0/1
Answer: C