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Authentic C-THR96-2311 Exam Hub, Valid C-THR96-2311 Vce Dumps | Study C-THR96-2311 Center - FreeTorrent

C-THR96-2311

Exam Code: C-THR96-2311

Exam Name: SAP Certified Application Associate - SAP SuccessFactors Workforce Analytics Technical Consultant 2H/2023

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
次の展示に示すAzureリソースの階層があります。

RG1、RG2、およびRG3はリソースグループです。
RG2には、VM1という名前の仮想マシンが含まれています。
次の表に示すユーザーに、役割ベースのアクセス制御(RBAC)の役割を割り当てます。

次の各ステートメントについて、ステートメントがtrueの場合は、[はい]を選択します。それ以外の場合は、[いいえ]を選択します。
注:正しい選択はそれぞれ1ポイントの価値があります。

Answer:
Explanation:
Explanation


NEW QUESTION: 2
XPath expressions are often used by: Select the correct answer.
A. XSLT and WSDL
B. XSLT and XQuery
C. XQuery and SOAP
D. XQuery only
Answer: B

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:

Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. ShippingCountry) cs WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, COUNT(OrderAmount) AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID ORDER BY OrderAmount DESC
C. SELECT CustomerID, CustomerName, ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName,
D. SELECT CustomerID, CustomerName, ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY c.CustomerID ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName,
E. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(OrderAmount) DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID Where o.Rnk = 1
F. ShippingCountry) cs WHERE Rnk = 1
G. ShippingCountry, RANK() OVER (PARTITION BY c. CustomerID ORDER BY o. OrderAmount DESC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName,
Answer: B

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