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NEW QUESTION: 1
While investigating beaconing Malware, an analyst can narrow the search quickly by using which of the
following watchlists in the McAfee SIEM?
A. MTI Suspicious and Malicious
B. TSI Suspicious and Malicious
C. GTI Suspicious and Malicious
D. MTIE Suspicious and Malicious
Answer: C

NEW QUESTION: 2
A company is considering making material adaptations to its warehouse and equipment. These costs will be $25,000,000 and will have a benefit period of 10 years. The income tax rate during this period will be 30%. The company is considering the effects of capitalizing the costs versus expensing the cost.
Which of the following effects will occur if the costs are expensed rather than capitalized?
A. Expensing will cause the return on assets in later years to be lower
B. Expensing will cause income to be greater in the years after the first year by $1,750,000 per year
C. Expensing will cause the return on equity to be lower in later years
Answer: B
Explanation:
In the years following the year the costs were incurred, there will be no expense if the costs were expensed in the first year. However, if costs were capitalized, there would be a $2,500,000 depreciation cost, which, after the tax effects (.3 x $2,500,000), would make income less by $1,750,000.

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively/ Both tables contain the following columns:

You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
G. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
H. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
Answer: G
Explanation:
Explanation
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php