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NEW QUESTION: 1
When SecureXL is enabled, all packets should be accelerated, except packets that match the following
conditions:
A. All IPv6 Traffic
B. All packets that match a rule whose source or destination is the Outside Corporate Network
C. All UDP packets
D. CIFS packets
Answer: D

NEW QUESTION: 2
お客様が、実行中のz / OS LPARに中央処理装置（CP）を同時に追加したいのですが、予約済みプロセッサーが定義されていません。
この追加のプロセッサーをLPARに追加するには、何をしなければなりませんか？
A. z / OSでオンラインでCPを構成します。
B. LPARを停止して現在のプロファイルを無効にします。必要なプロセッサ数でプロファイルを更新します。新しいプロファイルを有効にしてLPARをIPLします。
C. 実行中のLPARにCPを追加するために、HMC / SE（サポート・エレメント）でChange Running Systemを呼び出します。z/ OSでCPをオンラインで構成します。
D. 新しいプロファイルを動的に更新してアクティブにします。
Answer: B
Explanation:
適切なPFT（プロファイルテーブルエントリ）を使用すると、CP、ZIIP、IFL、およびICSFプロセッサをLPARに追加できます。
参照先：IBM z13およびIBM z13s技術紹介（2016年3月）、90ページ

NEW QUESTION: 3
Which question would you use to uncover opportunities for protecting the digital enterprise?
A. What type of devices do employees use to access the wireless network?
B. Are you interested in helping IT become more strategic, working as a line of business (LOB) partner?
C. How long is it taking IT to deploy new applications?
D. Do you plan to use a hybrid or private cloud environment?
Answer: D

NEW QUESTION: 4
You are a database developer of a Microsoft SQL Server 2016 database. You are designing a table that will store Customer data from different sources. The table will include a column that contains the CustomerID from the source system and a column that contains the SourceID. A sample of this data is as shown in the following table. You need to ensure that the table has no duplicate CustomerID within a SourceID. You also need to ensure that the data in the table is in the order of SourceID and then CustomerID.
Which Transact- SQL statement should you use?
A. CREATE TABLE Customer
(SourceID int NOT NULL PRIMARY KEY CLUSTERED,
CustomerID int NOT NULL UNIQUE,
CustomerName varchar(255) NOT NULL);
B. CREATE TABLE Customer
(SourceID int NOT NULL,
CustomerID int NOT NULL,
CustomerName varchar(255) NOT NULL,
CONSTRAINT PK_Customer PRIMARY KEY CLUSTERED
(SourceID, CustomerID));
C. CREATE TABLE Customer
(SourceID int NOT NULL,
CustomerID int NOT NULL PRIMARY KEY CLUSTERED,
CustomerName varchar(255) NOT NULL);
D. CREATE TABLE Customer
(SourceID int NOT NULL IDENTITY,
CustomerID int NOT NULL IDENTITY,
CustomerName varchar(255) NOT NULL);
Answer: B