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AD5-E805

Exam Code: AD5-E805

Exam Name: Analytics Developer Expert Renewal

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
What is the main function of LPTS?
A. guarantee reliable transport service for network management requests
B. classify transit packets
C. filter routing updates
D. maintain the Internal Forwarding Information Base (IFIB)
Answer: D

NEW QUESTION: 2
実装グループは、テストベッドを使用して「概念実証」を実行しており、クライアント1とクライアント2の両方が209.65.200.241のWEBサーバーにアクセスする必要があります。ネットワークアドレス指定、ルーティングスキーム、DHCPサービス、NTPサービス、レイヤー2接続、FHRPサービス、およびデバイスセキュリティにいくつかの変更を加えた後、クライアント1が209.65.200.241アドレスにpingできないことを示すトラブルチケットが開かれました。
サポートされているコマンドを使用して、この障害の原因を特定し、次の質問に答えてください。
障害状態の解決策は何ですか?
A. グローバル構成で、no ip dhcp use vrf connectedコマンドを削除します。
B. IP DHCPプール設定の下で、no ip dhcp excluded-address 10.2.1.1 10.2.1.253コマンドを発行し、ip dhcp excluded-address 10.2.1.1 10.2.1.2コマンドを入力します。
C. IP DHCPプール構成で、network 10.2.1.0 255.255.255.0コマンドを削除し、network 10.1.4.0 255.255.255.0コマンドを入力します。
D. IP DHCPプール構成で、default -router 10.2.1.254コマンドを削除し、default-router 10.1.4.5コマンドを入力します。
Answer: B
Explanation:
On R4 the DHCP IP address is not allowed for network 10.2.1.0/24 which clearly shows the problem lies on R4 & the problem is with DHCP Ticket 14 : EIGRP Passive Interface Topology Overview (Actual Troubleshooting lab design is for below network design)
- Client Should have IP 10.2.1.3
- EIGRP 100 is running between switch DSW1 & DSW2
- OSPF (Process ID 1) is running between R1, R2, R3, R4
- Network of OSPF is redistributed in EIGRP
- BGP 65001 is configured on R1 with Webserver cloud AS 65002
- HSRP is running between DSW1 & DSW2 Switches
The company has created the test bed shown in the layer 2 and layer 3 topology exhibits.
This network consists of four routers, two layer 3 switches and two layer 2 switches.
In the IPv4 layer 3 topology, R1, R2, R3, and R4 are running OSPF with an OSPF process number 1.
DSW1, DSW2 and R4 are running EIGRP with an AS of 10. Redistribution is enabled where necessary.
R1 is running a BGP AS with a number of 65001. This AS has an eBGP connection to AS 65002 in the ISP's network. Because the company's address space is in the private range.
R1 is also providing NAT translations between the inside (10.1.0.0/16 & 10.2.0.0/16) networks and outside (209.65.0.0/24) network.
ASW1 and ASW2 are layer 2 switches.
NTP is enabled on all devices with 209.65.200.226 serving as the master clock source.
The client workstations receive their IP address and default gateway via R4's DHCP server.
The default gateway address of 10.2.1.254 is the IP address of HSRP group 10 which is running on DSW1 and DSW2.
In the IPv6 layer 3 topology R1, R2, and R3 are running OSPFv3 with an OSPF process number
6.
DSW1, DSW2 and R4 are running RIPng process name RIP_ZONE.
The two IPv6 routing domains, OSPF 6 and RIPng are connected via GRE tunnel running over the underlying IPv4 OSPF domain. Redistrution is enabled where necessary.
Recently the implementation group has been using the test bed to do a `proof-of-concept' on several implementations. This involved changing the configuration on one or more of the devices.
You will be presented with a series of trouble tickets related to issues introduced during these configurations.
Note: Although trouble tickets have many similar fault indications, each ticket has its own issue and solution.
Each ticket has 3 sub questions that need to be answered & topology remains same.
Question-1 Fault is found on which device,
Question-2 Fault condition is related to,
Question-3 What exact problem is seen & what needs to be done for
solution
The neighborship between R4 and DSW1 wasn't established. Client 1 can't ping R4 The Configuration on R4 router eigrp 10 passive-interface default redistribute ospf 1 route-map OSPF->EIGRP network 10.1.4.4 0.0.0.3 network 10.1.4.8 0.0.0.3 default-metric 10000 100 255 1 10000 no auto-summary

NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.

If one or more students have the same average, the same rank must be given to these students.

Consecutive ranks must be skipped when the same rank is assigned.

Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: H
Explanation:
Explanation/Reference:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx

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