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SASInstitute A00-451 New Study Plan | A00-451 Valid Dumps Files & A00-451 Exam Vce - FreeTorrent

A00-451

Exam Code: A00-451

Exam Name: Administering SAS Viya

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
Examine this description of the TRANSACTIONS table:

Which two SQL statements execute successfully? (Choose two.)
A. SELECT customer_id AS CUSTOMER-ID, transaction_date AS TRANS_DATE, amount + 100 "DUES AMOUNT" FROM transactions;
B. SELECT customer_id CUSTID, transaction_date TRANS_DATE, amount + 100 DUES FROM transactions;
C. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS DATE, amount + 100 "DUES" FROM transactions;
D. SELECT customer_id AS 'CUSTOMER-ID', transaction_date AS DATE, amount + 100 'DUES AMOUNT' FROM transactions;
E. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS "DATE", amount + 100 DUES FROM transactions;
Answer: B,E

NEW QUESTION: 2






A. Option D
B. Option A
C. Option B
D. Option C
Answer: D

NEW QUESTION: 3
The perimeter of a rectangle is 136, what is the area of the rectangle?
(1) The length is more than twice the width.
(2) The length and width are both prime numbers larger than 30.
A. Either statement BY ITSELF is sufficient to answer the question.
B. Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, even though NEITHER statement BY ITSELF is sufficient.
C. Statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question, requiring more data pertaining to the problem.
D. Statement (2) BY ITSELF is sufficient to answer the question, but statement (1) by itself is not.
E. Statement (1) BY ITSELF is sufficient to answer the question, but statement (2) by itself is not.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Define L as the length and W as the width.
2L + 2W = 136 ---> L + W = 68. We need one more equation in order to find the area.
Statement (1) does not give you exact values and therefore it's not sufficient.
Statement (2) tells us that both L and W are prime numbers larger than 30, using the equation in the question; the only option to get 68 is with 31 and 37. This statement is sufficient; the area is 31 x 37.

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