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NEW QUESTION: 1
The authority of a private person to make an arrest is usually:
A. None of the above
B. The same as a deputized guard
C. A matter of state law
D. Unlimited
E. Limited to those cases where a warrant is obtained
Answer: C

NEW QUESTION: 2
Refer to the exhibit. Which item is depicted in this output?

A. Windows Security audit log
B. packet capture exported text
C. VLAN 10 traffic
D. NetFlow data
Answer: D

NEW QUESTION: 3
Click the Exhibit button.

Traffic is flowing through the interfaces in the exhibit as follows:
On ge-0/0/2.0, IPv4 traffic has a throughput rate of 4 Mbps, and the burst size counter is at 200 KB.
On ge-0/0/2.0, IPv6 traffic has a throughput rate of 7 Mbps, and the burst size counter is at 550 KB.
On ge-0/0/3.0, IPv4 traffic has a throughput rate of 5 Mbps, and the burst size counter is at 250 KB.
On ge-0/0/3.1, IPv6 traffic has a throughput rate of 12 Mbps, and the burst size counter is at 450 KB.
Which statement describes what is happening?
A. IPv6 traffic on ge-0/0.3.1 is being dropped; all other traffic is unaffected.
B. IPv4 traffic on ge-0/0/2.0 is unaffected; IPv6 traffic on ge-0/0/2.0 is being dropped; IPv4 traffic on ge-
0/0/3.0 is unaffected; IPv6 traffic on ge-0/0/3.1 is being dropped.
C. All IPv4 and IPv6 traffic on ge-0/0/2 and ge-0/0/3 is being dropped.
D. IPv4 traffic on ge-0/0/2.0 is being dropped; IPv6 traffic on ge-0/0/2.0 is being dropped; IPv4 traffic on ge-0/0/3.0 is unaffected; IPv6 traffic on ge-0/0/3.1 is unaffected.
Answer: B

NEW QUESTION: 4
Welche der folgenden SQL-Abfragen zählt die Anzahl der Vorkommen für jeden Wert des Feldes order_type in den Tabellenreihenfolgen?
A. SELECT AUTO_COUNT FROM orders COUNT order_type;
B. SELECT COUNT (*) FROM Bestellungen ORDER BY order_type;
C. COUNT (SELECT order_type FROM orders);
D. SELECT order_type, COUNT (*) FROM orders GROUP BY order_type;
E. SELECT order_type, COUNT (*) FROM orders WHERE order_type = order_type;
Answer: D
Explanation:
Erläuterung
Abschnitt: Shells, Scripting und Datenverwaltung