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2024 4A0-260 Valid Test Format, Pass Leader 4A0-260 Dumps | Pass Nokia Advanced Optical Network Management with 1350 OMS Test - FreeTorrent

4A0-260

Exam Code: 4A0-260

Exam Name: Nokia Advanced Optical Network Management with 1350 OMS

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
SIMULATION
Scenario:
You work for SWITCH.com. They have just added a new switch (SwitchB) to the existing network as shown in the topology diagram.
RouterA is currently configured correctly and is providing the routing function for devices on SwitchA and SwitchB. SwitchA is currently configured correctly, but will need to be modified to support the addition of SwitchB. SwitchB has a minimal configuration. You have been tasked with competing the needed configuring of SwitchA and SwitchB. SwitchA and SwitchB use Cisco as the enable password.
Configuration Requirements for SwitchA
The VTP and STP configuration modes on SwitchA should not be modified.
* SwitchA needs to be the root switch for vlans 11, 12, 13, 21, 22 and 23. All other vlans should be left are their default values.
Configuration Requirements for SwitchB
* Vlan 21
Name: Marketing
will support two servers attached to fa0/9 and fa0/10
* Vlan 22
Name: Sales
will support two servers attached to fa0/13 and fa0/14
* Vlan 23
o Name: Engineering
o will support two servers attached to fa0/15 and fa0/16
* Access ports that connect to server should transition immediately to forwarding state upon detecting the connection of a device.
* SwitchB VTP mode needs to be the same as Switch A.
* SwitchB must operate in the same spanning tree mode as SwitchA
* No routing is to be configured on SwitchB
* Only the SVI vlan 1 is to be configured and it is to use address 192.168.1.11/24 Inter-switch Connectivity Configuration Requirements
* For operational and security reasons trunking should be unconditional and Vlans 1, 21, 22 and 23 should tagged when traversing the trunk link.
* The two trunks between SwitchA and SwitchB need to be configured in a mode that allows for the maximum use of their bandwidth for all vlans. This mode should be done with a non-proprietary protocol, with SwitchA controlling activation.
* Propagation of unnecessary broadcasts should be limited using manual pruning on this trunk link.

Answer:
Explanation:
Here are steps:
hostname SWITCH_B
!
!
vlan 21
name Marketing
vlan 22
name Sales
vlan 23
name Engineering
!
!
interface FastEthernet0/3
switchport trunk allowed vlan 1,21-23
channel-protocol lacp
channel-group 1 mode passive
switchport mode trunk
!
interface FastEthernet0/4
switchport trunk allowed vlan 1,21-23
channel-protocol lacp
channel-group 1 mode passive
switchport mode trunk
!
interface FastEthernet0/9
switchport access vlan 21
switchport mode access
spanning-tree portfast
!
interface FastEthernet0/10
switchport access vlan 21
switchport mode access
spanning-tree portfast
!
interface FastEthernet0/13
switchport access vlan 22
switchport mode access
spanning-tree portfast
!
!
interface FastEthernet0/14
switchport access vlan 22
switchport mode access
spanning-tree portfast
!
interface FastEthernet0/15
switchport access vlan 23
switchport mode access
spanning-tree portfast
!
interface FastEthernet0/16
switchport access vlan 23
switchport mode access
spanning-tree portfast
!
!
interface GigabitEthernet1/1
!
interface GigabitEthernet1/2
!
interface Port-channel 1
switchport mode trunk
switchport trunk encapsulation dot1q
spanning-tree allowed vlans 1,21-23
!
interface Vlan1
ip address 192.168.1.11 255.255.255.0
!
end
SWITCH_B(config)#
hostname SWITCH_A
!
panning-tree vlan 11 root primary
spanning-tree vlan 12 root primary
spanning-tree vlan 13 root primary
spanning-tree vlan 21 root primary
spanning-tree vlan 22 root primary
spanning-tree vlan 23 root primary
!
interface FastEthernet0/3
switchport trunk allowed vlan 1,21-23
channel-protocol lacp
channel-group 1 mode active
switchport mode trunk
!
interface FastEthernet0/4
switchport trunk allowed vlan 1,21-23
channel-protocol lacp
channel-group 1 mode active
switchport mode trunk
!
interface FastEthernet0/21
switchport access vlan 21
switchport mode access
!
interface FastEthernet0/22
switchport access vlan 22
switchport mode access
!
interface FastEthernet0/23
switchport access vlan 23
switchport mode access
!
interface GigabitEthernet1/1
!
interface GigabitEthernet1/2
!
interface Port-channel 1
!
interface Vlan1
no ip address
shutdown
!
ip default-gateway 192.168.1.1
!
!
End

NEW QUESTION: 2
Your network contains an Active Directory domain named contoso.com. The domain contains a server
named Server1 that runs Windows Server 2016.
Server1 has IP Address Management (IPAM) installed. IPAM is configured to use the Group Policy based
provisioning method. The prefix for the IPAM Group Policy objects (GPOs) is IP.
From Group Policy Management, you manually rename the IPAM GPOs to have a prefix of IPAM.
You need to modify the GPO prefix used by IPAM.
What should you do?
A. Click Configure server discovery in Server Manager.
B. Run the Invoke-IpamGpoProvisioning cmdlet.
C. Click Provision the IPAM server in Server Manager.
D. Run the Set-IpamConfiguration cmdlet.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
The Set-IpamConfiguration cmdlet modifies the configuration for the computer that runs the IPAM server.
The -GpoPrefix<String> parameter specifies the unique Group Policy object (GPO) prefix name that IPAM
uses to create the group policy objects. Use this parameter only when the value of the ProvisioningMethod
parameter is set to Automatic.
References:
https://docs.microsoft.com/en-us/powershell/module/ipamserver/set-ipamconfiguration?view=win10-ps

NEW QUESTION: 3
McCarver Inc. is considering the following mutually exclusive projects:
Project A Project B
TimeCash FlowCash Flow
0-$5,000-$5,000
1200 3,000
2800 3,000
33,000 800
45,000 200
At what cost of capital will the net present value of the two projects be the same?
A. 16.15%
B. 17.72%
C. 17.80%
D. 15.68%
E. 16.25%
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Find the differences between the two projects' respective cash flows as follows:
(Project A CF - Project B CF).
CF(0) = -5,000 - (-5,000) = 0.
CF(1) = 200 - 3,000 = -2,800.
CF(2) = -2,200.
CF(3) = 2,200.
CF(4) = 4,800.
Enter these CFs and find the IRR = 16.15% which is the crossover rate.

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