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Exam 4A0-115 Pattern, Nokia 4A0-115 Free Brain Dumps | New 4A0-115 Test Prep - FreeTorrent

4A0-115

Exam Code: 4A0-115

Exam Name: Nokia Ethernet Virtual Private Network Services

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
A client device associates with an SSID provisioned with 802.1X authentication. The client is set for LEAP authentication. EAP termination (AAA Fastconnect) is enabled on the controller. But the client continuously cycles through the authentication process. Which of the following could cause this?
A. The VLAN is missing for the SSID.
B. The client has an expired or revoked server certificate.
C. The Radius server is rejecting the client credentials.
D. The controller does not support LEAP in this mode.
E. The DHCP server is not enabled.
Answer: D

NEW QUESTION: 2
What is TRUE about the PRPC command line utility that imports and exports archives? (Choose One)
A. It does not require the Pega-ImportExport agent running
B. It communicates with the source and target systems over SOAP
C. It cannot use a Rule-Admin-Product to export rules
D. It is installed with PRPC by default
Answer: A

NEW QUESTION: 3
標準に合わせるプロセスを加速するのに役立つツールはどれですか?この質問には3つの回答があります
A. スターターシステム
B. セルフサービス構成Ul
C. コンテンツライフサイクル管理
D. テストスクリプト
E. 業務プロセスフロー
Answer: A,D,E

NEW QUESTION: 4
What is the value of x?
(1) 22 < 3x + 1 < 28
(2) x is an integer.
A. Statement (2), BY ITSELF, will suffice to solve the problem, but NOT statement (1) by itself.
B. The problem can be solved using statement (1) and statement (2) TOGETHER, but not ONLY statement (1) or statement (2).
C. Statement (1), BY ITSELF, will suffice to solve the problem, but NOT statement (2) by itself.
D. The problem can be solved using EITHER statement (1) only or statement (2) only.
E. The problem CANNOT be solved using statement (1) and statement (2) TOGETHER.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Solve the compound inequality in statement (1). 22 < 3x + 1 < 28. Subtract 1 from each part of the

inequality. 22 - 1 < 3x + 1 - 1 < 28 - 1. Divide each part by 3. The
result is that x is some number between 7 and 9; thus, statement (1) is not sufficient. Statement (2), together with statement (1), is sufficient, and the answer is conclusively one value - namely, 8.

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