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Exam Code: 301a
Exam Name: BIG-IP LTM Specialist: Architect Set-Up & Deploy
Version: V22.75
Q & A: 580 Questions and Answers
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NEW QUESTION: 1
A client device associates with an SSID provisioned with 802.1X authentication. The client is set for LEAP authentication. EAP termination (AAA Fastconnect) is enabled on the controller. But the client continuously cycles through the authentication process. Which of the following could cause this?
A. The controller does not support LEAP in this mode.
B. The client has an expired or revoked server certificate.
C. The VLAN is missing for the SSID.
D. The Radius server is rejecting the client credentials.
E. The DHCP server is not enabled.
Answer: A
NEW QUESTION: 2
What is TRUE about the PRPC command line utility that imports and exports archives? (Choose One)
A. It cannot use a Rule-Admin-Product to export rules
B. It does not require the Pega-ImportExport agent running
C. It communicates with the source and target systems over SOAP
D. It is installed with PRPC by default
Answer: B
NEW QUESTION: 3
標準に合わせるプロセスを加速するのに役立つツールはどれですか?この質問には3つの回答があります
A. セルフサービス構成Ul
B. スターターシステム
C. テストスクリプト
D. コンテンツライフサイクル管理
E. 業務プロセスフロー
Answer: B,C,E
NEW QUESTION: 4
What is the value of x?
(1) 22 < 3x + 1 < 28
(2) x is an integer.
A. Statement (2), BY ITSELF, will suffice to solve the problem, but NOT statement (1) by itself.
B. The problem can be solved using statement (1) and statement (2) TOGETHER, but not ONLY statement (1) or statement (2).
C. Statement (1), BY ITSELF, will suffice to solve the problem, but NOT statement (2) by itself.
D. The problem can be solved using EITHER statement (1) only or statement (2) only.
E. The problem CANNOT be solved using statement (1) and statement (2) TOGETHER.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Solve the compound inequality in statement (1). 22 < 3x + 1 < 28. Subtract 1 from each part of the
inequality. 22 - 1 < 3x + 1 - 1 < 28 - 1. Divide each part by 3. The
result is that x is some number between 7 and 9; thus, statement (1) is not sufficient. Statement (2), together with statement (1), is sufficient, and the answer is conclusively one value - namely, 8.
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