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NEW QUESTION: 1
Refer to the exhibit.

Switches A and C are running PVST+ STP, and Switch B is running 802.1Q STP. If the BPDU of the root in VLAN 1 is better than the BPDU of the root in VLAN 2, then there is no blocking port in the VLAN 2 topology. The BPDU of VLAN 2 never makes a "full circle" around the topology; it is replaced by the VLAN 1 BPDU on the B-C link, because B runs only one STP merged with VLAN 1 STP of PVST+. Thus, there is a forwarding loop.
What does PVST+ do to correct this?
A. Switch B sends PVST+ BPDUs of VLAN 1 (to the SSTP address that is flooded by Switch A) towards Switch C. Switch C will put port C-B into a type-inconsistent state, which prevents the loop.
B. Switch C sends PVST+ BPDUs of VLAN 2 (to the SSTP address that is flooded by Switch B) towards Switch Switch A will put port C-B into a type-inconsistent state, which prevents the loop.
C. Switch A sends PVST+ BPDUs of VLAN 2 (to the SSTP address that is flooded by Switch B) towards Switch C. Switch C will put port C-B into a type-inconsistent state, which prevents the loop.
D. Switch A sends PVST+ BPDUs of VLAN 1 (to the SSTP address that is flooded by Switch B) towards Switch B. Switch A will put port C-B into a type-inconsistent state, which prevents the loop.
Answer: C

NEW QUESTION: 2
You have a computer named Computer1 that runs Windows 10. Computer1 contains a registry key named Key1 that has the values shown in the exhibit. (Click the Exhibit tab.).

You have a Registration Entries (.reg) file named File1.reg that contains the following text.
Windows Registry Editor Version 5.00
[HKEY_LOCAL_MACHINE\SOFTWARE\Key1]
"String1"=-
@="2"
You need to identify the effect of importing File1.reg to Computer1.
What should you identify? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

Box 1: String1 will be deleted.
To delete a value, append equals and then minus to the value. For example:
"String1"=-
Box 2: Value1 will have a value of 1
@="2" sets the default value to 1 but Value1 already has a DWORD value.
A DWORD (32-bit) value is a hexadecimal value. Value1 is 0x00000001 which is 1.
References:
https://www.computerhope.com/issues/ch000848.htm
https://www.computerperformance.co.uk/vista/reg-create/

NEW QUESTION: 3
Given the code fragments:

Which modification enables the code to compile?
A:

B:

C:

D:

A. Option C
B. Option D
C. Option B
D. Option A
Answer: A

NEW QUESTION: 4
すべてのコストと収益のプロフィットセンターアカウンティングを実装するには、新しいGLで次のうちどれをアクティブにする必要がありますか？ （2つ選択）
A. リアルタイム統合CO / FI
B. シナリオセグメントレポート
C. シナリオ利益センタの更新
D. 文書分割
Answer: A,C