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NEW QUESTION: 1
A server administrator tells you that the server network is potentially under attack. Which piece of information is critical to begin your network investigation?
A. administrator password for the servers
B. IP addresses/subnets used for the servers
C. cabinet location of the servers
D. OS that is used on the servers
Answer: B

NEW QUESTION: 2
How does the weight and height reduction delivery option change the delivery configuration of a XIV Gen3?
A. Removes the top four modules from the rack and ships them separately
B. Removes all of the modules and UPSes from the rack and ships them separately
C. Removes all of the modules from the rack and ships them separately
D. Removes the top four modules and UPSes from the rack and ships them separately
Answer: D

NEW QUESTION: 3
Refer to the exhibit.

Which address and mask combination represents a summary of the routes learned by EIGRP?
A. 192.168.25.28 255.255.255.240
B. 192.168.25.28 255.255.255.252
C. 192.168.25.16 255.255.255.240
D. 192.168.25.16 255.255.255.252
E. 192.168.25.0 255.255.255.240
F. 192.168.25.0 255.255.255.252
Answer: C
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of
them:
+
192.168.25.16
+
192.168.25.20
+
192.168.25.24
+
192.168.25.28 -> The increment should bE. 28 - 16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) = 255.255.255.240 So the best answer should be 192.168.25.16 255.255.255.240

NEW QUESTION: 4

A. NAT
B. Transient
C. Fixed
D. DHCP
E. Bridged
Answer: B,C,D
Explanation:
Option Description