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Exam Code: 1z0-1196-25
Exam Name: Oracle Utilities Customer to Meter and Customer Cloud Service 2025 Implementation Professional
Version: V22.75
Q & A: 580 Questions and Answers
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NEW QUESTION: 1
A client device associates with an SSID provisioned with 802.1X authentication. The client is set for LEAP authentication. EAP termination (AAA Fastconnect) is enabled on the controller. But the client continuously cycles through the authentication process. Which of the following could cause this?
A. The DHCP server is not enabled.
B. The controller does not support LEAP in this mode.
C. The VLAN is missing for the SSID.
D. The client has an expired or revoked server certificate.
E. The Radius server is rejecting the client credentials.
Answer: B
NEW QUESTION: 2
What is TRUE about the PRPC command line utility that imports and exports archives? (Choose One)
A. It communicates with the source and target systems over SOAP
B. It is installed with PRPC by default
C. It cannot use a Rule-Admin-Product to export rules
D. It does not require the Pega-ImportExport agent running
Answer: D
NEW QUESTION: 3
標準に合わせるプロセスを加速するのに役立つツールはどれですか?この質問には3つの回答があります
A. セルフサービス構成Ul
B. コンテンツライフサイクル管理
C. 業務プロセスフロー
D. スターターシステム
E. テストスクリプト
Answer: C,D,E
NEW QUESTION: 4
What is the value of x?
(1) 22 < 3x + 1 < 28
(2) x is an integer.
A. The problem can be solved using statement (1) and statement (2) TOGETHER, but not ONLY statement (1) or statement (2).
B. Statement (2), BY ITSELF, will suffice to solve the problem, but NOT statement (1) by itself.
C. Statement (1), BY ITSELF, will suffice to solve the problem, but NOT statement (2) by itself.
D. The problem CANNOT be solved using statement (1) and statement (2) TOGETHER.
E. The problem can be solved using EITHER statement (1) only or statement (2) only.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Solve the compound inequality in statement (1). 22 < 3x + 1 < 28. Subtract 1 from each part of the
inequality. 22 - 1 < 3x + 1 - 1 < 28 - 1. Divide each part by 3. The
result is that x is some number between 7 and 9; thus, statement (1) is not sufficient. Statement (2), together with statement (1), is sufficient, and the answer is conclusively one value - namely, 8.
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