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New 156-835 Test Cram - CheckPoint 156-835 Exam Simulator Free, 156-835 Relevant Answers - FreeTorrent

156-835

Exam Code: 156-835

Exam Name: Check Point Certified Maestro Expert

Version: V22.75

Q & A: 580 Questions and Answers

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NEW QUESTION: 1
Given the line from a name service configuration file:
hosts: files nis nisplus dns
Which statement correctly describes the behavior of the name service switch?
A. The attempt to locate a host's IP address would begin with DNS and would continue, if necessary, to use each name service, reading right to left, and stopping if the IP address was found, any of the name services were unavailable, or if the name service list was completed.
B. The attempt to locate a host's IP address would begin with DNS and would continue, if necessary, to use each name service, reading right to left, and stopping only if the IP address was found or if the name service list was completed.
C. The attempt to locate a host's IP address would begin with local files and would continue, if necessary, to use each name service, reading left to right, and stopping if the IP address was found, if any of the name services were unavailable, or if the name service list was completed.
D. The attempt to locate a host's IP address would begin with local files and would continue, if necessary, to use each name service, reading left to right, and stopping only if the IP address was found or if the name service list was completed.
Answer: D

NEW QUESTION: 2
Project management processes describe project work, while product-oriented management processes specify the project's product. Therefore, a project management process and a product-oriented management process______________.
A. Are defined by the project life cycle
B. Overlap and interact throughout the project
C. Are similar for each application area
D. Are concerned with describing and organizing project work
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Project management processes and product-oriented management processes must be integrated throughout the project's life cycle, given their close relationship. In some cases, it is difficult to distinguish between the two. For example, knowing how the project will be created aids in determining the project's scope. However, the project life cycle is independent from that of the product.

NEW QUESTION: 3
A customer has purchased Avaya Aura Contact Center (AACC) with the correct licensing to provide Open Queue session licenses, and to provide agent licenses for the required multimedia contact types.
Where is Open Queue initially enabled in AACC?
A. Contact Center License Manager > Configuration > Contact Center Licensing tab
B. Ignition Wizard configuration > Licensing tab
C. Contact Center Manager Administration (CCMA) > Configuration, Applications > LM
Service Configuration Setuptab
D. CCMS > Multimedia Commissioning > Multimedia Licensing tab
Answer: A

NEW QUESTION: 4
Which of these is the equation used to derive a 64 Kbps bit rate?
A. 2 x 4-bit code words x 8 kHz
B. 8 kHz x 8-bit code words
C. 2 x 8 kHz x 4-bit code words
D. 2 x 4 kHz x 8-bit code words
Answer: D
Explanation:
While the human ear can sense sounds from 20 to 20, 000 Hz, and speech encompasses sounds
from about 200 to 9000 Hz, the telephone channel was designed to operate at about 300 to 3400
Hz. This economical range carries enough fidelity to allow callers to identify the party at the far end
and sense their mood. Nyquist decided to extend the digitization to 4000 Hz, to capture higher-
frequency sounds that the telephone channel may deliver. Therefore, the highest frequency for
voice is 4000 Hz. According to Nyquist theory, we must double the highest frequency, so 2x4kHz
= 8kHz.
Each sample will be encoded into a 8-bit code. Therefore 8kHz x 8-bit code = 64 Kbps (notice
about the unit Kbps: 8kHz = 8000 samples per second so 8000 x 8-bit = 64000 bit per second =
64 Kilobit per second = 64 Kbps)
Link: http://encyclopedia2.thefreedictionary.com/Nyquist+theorem
Note:
Nyquist theory:
"When sampling a signal (e.g., converting from an analog signal to digital), the sampling frequency
must be greater than twice the bandwidth of the input signal in order to be able to reconstruct the
original perfectly from the sampled version."

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