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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of customers who have either deposit accounts or loan accounts, but not both types of accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
B. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo = L.CustNo
C. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
G. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
Answer: G
Explanation:
Explanation
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

NEW QUESTION: 2
Your network contains an Active Directory domain named contoso.com.
The user account for a user named User1 is in an organizational unit (OU) named OU1.
You need to enable User1 to sign in as [email protected].
Solution: From Windows PowerShell, You run Set-ADuser User1 -UserPrincipalName [email protected].
Does this meet the goal?
A. Yes
B. No
Answer: A

NEW QUESTION: 3

A. 0
B. 1
C. 2
D. 3
E. 4
F. 5
Answer: C,F
Explanation:
Explanation
By default, the Cisco IOS software command-line interface (CLI) has two levels of access to commands: user EXEC mode (level 1) and privileged EXEC mode (level 15).
Source:
http://www.cisco.com/c/en/us/td/docs/ios/12_2/security/configuration/guide/fsecur_c/scfpass.html

NEW QUESTION: 4
配信APIエラーを解決する必要があります。あなたは何をするべきか？
A. Entity Frameworkの慣習的な実行方法を呼び出します。
B. Entity FrameworkのEnableRetryOnFailure機能を使用して、サーキットブレーカーパターンを実装します。
C. Entity FrameworkのEnableRetryOnFailure機能を使用して指数的バックオフを実装します。
D. Entity FrameworkのEnableRetryOnFailure機能を使用して簡単な再試行を実装します。
Answer: D
Explanation:
Scenario: The Delivery API intermittently throws the following exception:

A useful method to get rid of this error is to use RETRY LOGIC of Entity Framework 1.1.0 services.AddDbContext<DbContext>(options => options.UseSqlServer('yourconnectionstring',
...sqlServerOptionsAction: sqlOptions =>
...{
......sqlOptions.EnableRetryOnFailure(
.........maxRetryCount: 5,
.........maxRetryDelay: TimeSpan.FromSeconds(30),
.........errorNumbersToAdd: new List<int>() { 19 });
...}));
In Retry logic, error 19 is not included. So you have to pass the error code 19 to set retry logic for error code 19.
References:
https://stackoverflow.com/questions/47558062/error-19-physical-connection-error/47559967