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Exam Code: 156-583
Exam Name: Check Point Certified Troubleshooting Administrator - R82 (CCTA)
Version: V22.75
Q & A: 580 Questions and Answers
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NEW QUESTION: 1
Which of the following would BEST ensure that security risk assessment is integrated into the life cycle of major IT projects?
A. Integrating the risk assessment into the internal audit program
B. Having the information security manager participate on the project setting committees
C. Applying global security standards to the IT projects
D. Training project managers on risk assessment
Answer: C
NEW QUESTION: 2
A. Option C
B. Option A
C. Option D
D. Option B
Answer: A
Explanation:
The WatchKey take() method retrieves and removes next watch key, waiting if none are yet present.
Note: A watch service that watches registered objects for changes and events. For example a file manager may use a watch service to monitor a directory for changes so that it can update its display of the list of files when files are created or deleted. A Watchable object is registered with a watch service by invoking its register method, returning a WatchKey to represent the registration. When an event for an object is detected the key is signalled, and if not currently signalled, it is queued to the watch service so that it can be retrieved by consumers that invoke the poll or take methods to retrieve keys and process events. Once the events have been processed the consumer invokes the key's reset method to reset the key which allows the key to be signalled and re-queued with further events.
Reference: Interface WatchService
NEW QUESTION: 3
Your table space DB1.TS1 is currently index-partitioned. Which steps should be performed at a minimum to make it a partitioned-by-range table space?
A. Drop the partitioning index, ALTER the table definition by adding partition ranges to the existing table definition, then issue ALTER TABLESPACE with a valid SEGSIZE > 0
B. Make the table space table-partitioned, then issue ALTER TABLESPACE with a validSEGSIZE > 0
C. Issue ALTER TABLESPACE with a valid SEGSIZE > 0
D. Drop the partitioning index, ALTER the table definition by addingpartition ranges to the existing table definition, create a partitioned index and issue ALTER TABLESPACE with a valid SEGSIZE > 0
Answer: B
NEW QUESTION: 4
In the case of Web services applications, Email, database applications, such as reading and writing small files frequently, SAN performance is mainly determined by the bandwidth; video, mapping and other large files under sustained read and write operations, SAN performance is mainly determined by the IOPS.
A. True
B. False
Answer: B
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